This vignette is adapted from the official Armadillo A Deep Dive Into How R Fits a Linear Model.
For those interested in Econometrics, do yourself a favour and buy Econometrics by Prof. Bruce E. Hansen. I have unofficial re-written codes using Armadillo for his R examples.
The starting point to fit a linear regresion in R without using the lm
function is to create a design matrix and a response vector. The design matrix is a matrix where each row corresponds to an observation and each column corresponds to a predictor. The response vector is a vector of the same length as the number of observations.
For example, using the mtcars
dataset it is possible to create a design matrix to later estimate the linear regression coefficients for the model:
\[ \text{mpg}_i = \beta_0 + \beta_1 \times \text{weight}_i + e_i \]
For \(\beta_0\) and \(\beta_1\) to be estimated, the design matrix and the response vector are created as follows:
cbind(1, mtcars$wt)
x <- mtcars$mpg
y <-
head(x)
#> [,1] [,2]
#> [1,] 1 2.620
#> [2,] 1 2.875
#> [3,] 1 2.320
#> [4,] 1 3.215
#> [5,] 1 3.440
#> [6,] 1 3.460
head(y)
#> [1] 21.0 21.0 22.8 21.4 18.7 18.1
dim(x)
#> [1] 32 2
length(y)
#> [1] 32
Certainly, there is a more efficient way to create the design matrix and the response vector. The model.matrix
function can be used to create the design matrix and the model.response
function can be used to create the response vector:
model.matrix(mpg ~ wt, data = mtcars)
x <- model.response(model.frame(mpg ~ wt, data = mtcars)) y <-
The advantage of using these functions is that they handle factor variables more easily. For example, if the mtcars
dataset has a factor variable, the model.matrix
function will create one 0/1 column for each level of the factor variable.
To estimate the regression coefficients, the solve
function can be used:
solve(t(x) %*% x) %*% t(x) %*% y
#> [,1]
#> (Intercept) 37.285126
#> wt -5.344472
It can be verified that the coefficients are the same as the ones estimated by the lm
function:
lm(mpg ~ wt, data = mtcars)$coefficients
#> (Intercept) wt
#> 37.285126 -5.344472
However, the lm()
function does not use the solve
function to estimate the coefficients. Instead, it uses the QR decomposition and internal functions written in C and FORTRAN to estimate the coefficients.
Using ‘cpp11armadillo’ library, the regression coefficients can be estimated as follows:
const Mat<double>& X, const Col<double>& Y) {
vec ols_fit(// QR decomposition
mat Q, R;
qr_econ(Q, R, X);
// Least Squares Problem
vec betas = solve(trimatu(R), Q.t() * Y);
return betas;
}
cpp11::register]] doubles ols_(const doubles_matrix<>& x, const doubles& y) {
[[
mat X = as_Mat(x);
vec Y = as_Col(y);return as_doubles(ols_fit(X, Y));
}
Verify the equivalence:
all.equal(ols_(x,y), unname(coef(lm(mpg ~ wt, data = mtcars))))
1] TRUE [
The starting point to fit a Poisson regresion in R without using the glm
function is to create a design matrix and a response vector.
For example, using the mtcars
dataset it is possible to create a design matrix to later estimate the Poisson regression coefficients for the model:
\[ \log(\text{mpg}_i) = \beta_0 + \beta_1 \times \text{weight}_i + e_i \]
For \(\beta_0\) and \(\beta_1\) to be estimated, the design matrix and the response vector are created as follows:
model.matrix(mpg ~ wt, data = mtcars)
x <- log(mtcars$mpg) y <-
The Poisson regression coefficients can be estimated using the glm
function:
glm(mpg ~ wt, data = mtcars, family = poisson(link = "log"))$coefficients
#> (Intercept) wt
#> 3.8730232 -0.2823192
Estimating a Poisson regression is more complex than estimating a linear regression. The Poisson regression coefficients are estimated using an iterative algorithm known as the Iteratively Reweighted Least Squares (IRLS) algorithm. However, the IRLS algorithm can be simplified by using the weighted least squares method, which repeats a linear regression over the transformed data using the Poisson link until convergence.
Using ‘cpp11armadillo’ library, the Poisson regression coefficients can be estimated via IRLS as follows:
const Mat<double>& X, const Col<double>& Y, const Col<double>& W) {
vec ols_weighted_fit(// Create a diagonal matrix from the weight vector
mat W_diag = diagmat(W);
// Weighted least squares problem
mat XTWX = X.t() * W_diag * X;
vec XTWY = X.t() * W_diag * Y;
// Solve the system
vec betas = solve(XTWX, XTWY);
return betas;
}
const Mat<double>& X, const Col<double>& Y) {
vec poisson_fit(// Data transformation
0.1; // Initial guess for MU
vec MU = Y +
vec ETA = log(MU);
vec Z = ETA + (Y - MU) / MU;
// Iterate with initial values for the difference and the sum of sq residuals
double dif = 1;
double rss = 1;
double tol = 1e-10;
vec W;
vec betas, res;double rss2;
while (abs(dif) > tol) {
// Weights are the current estimates of MU
W = MU;
betas = ols_weighted_fit(X, Z, W);
ETA = X * betas;
MU = exp(ETA);
Z = ETA + (Y - MU) / MU;
res = Y - MU;
rss2 = sum(res % res);
dif = rss2 - rss;
rss = rss2;
}
return betas;
}
cpp11::register]] doubles poisson_(const doubles_matrix<>& x, const doubles& y) {
[[
mat X = as_Mat(x);
vec Y = as_Col(y);return as_doubles(poisson_fit(X, Y));
}
Verify the equivalence:
all.equal(poisson_(x,y), unname(coef(glm(mpg ~ wt, data = mtcars, family = poisson()))))
1] TRUE [
Note: The glm()
function shows warnings because it expects integer values for the response variable. However, the Poisson regression can be estimated with non-integer values for the response variable or the quasipoisson()
family can be used to suppress the warnings.